I have some jobs that run and will fill up disk drives if not pruned.<\/p>\n
I put together the simple script below that I can call with a directory and the number of files I want to keep. The oldest files will be deleted. I add it to cron jobs with a command in this pattern:<\/p>\n
~\/DelOverNumberFiles.sh ~\/public_html\/FrontDoor\/Camera\\ 01 200\r\nNote: there are 2 params, the \\ escapes the space before the 01<\/pre>\nCopy into DelOverNumberFiles.sh\r\n\r\n#!\/bin\/bash\r\n\r\nlimit=$2\r\ndir=$1\r\nCnt=0\r\nfor line in `ls -t \"$1\"`\r\ndo\r\n if [[ $Cnt -gt $limit ]]\r\n then\r\n rm \"$dir\/$line\"\r\n echo \"rm $dir\/$line\"\r\n fi\r\n Cnt=`expr $Cnt + 1`\r\ndone<\/pre>\nWhile I know this is not the most professional way to do this, I wanted something very simple I could play with and should have few dependencies so I could use it on shared servers that I do not have control over.<\/p>\n","protected":false},"excerpt":{"rendered":"
I have some jobs that run and will fill up disk drives if not pruned. I put together the simple script below that I can call with a directory and the number of files I want to keep. The oldest … Continue reading